11x^2+12x-7=0

Solution for 11x^2+12x-7=0 equation:

11x^2+12x-7=0

a = 11; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·11·(-7)
Δ = 452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{452}=\sqrt{4*113}=\sqrt{4}*\sqrt{113}=2\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{113}}{2*11}=\frac{-12-2\sqrt{113}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{113}}{2*11}=\frac{-12+2\sqrt{113}}{22}
$